125 lines
4.2 KiB
SQL
125 lines
4.2 KiB
SQL
-- Preflight (до миграций) для перехода на группы-когорты, курсы и перенос лаб/материалов.
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-- Только чтение. Запускать на копии рабочей БД до применения миграций.
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-- Пример:
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-- psql -h localhost -U lms -d lms -f deploy/preflight/groups-courses.sql
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\pset pager off
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\echo '=== 1. Группы, не подходящие под шаблон ^(.+)-([0-9])([0-9]+)(БО|МО)$ ==='
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SELECT id, name
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FROM identity.groups
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WHERE name !~ '^(.+)-([0-9])([0-9]+)(БО|МО)$'
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ORDER BY name;
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\echo '=== 2. Разобранные группы с одинаковым кортежем (stream, degree, number, course, enrollment_year) ==='
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WITH params AS (
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SELECT CASE
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WHEN EXTRACT(MONTH FROM now()) >= 9 THEN EXTRACT(YEAR FROM now())
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ELSE EXTRACT(YEAR FROM now()) - 1
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END::int AS academic_year_start
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),
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parsed AS (
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SELECT
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g.name,
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m[1] AS stream,
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m[2]::int AS course,
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m[3]::int AS number,
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m[4] AS degree,
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(SELECT academic_year_start FROM params) - (m[2]::int - 1) AS enrollment_year
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FROM identity.groups g
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CROSS JOIN LATERAL (
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SELECT regexp_match(g.name, '^(.+)-([0-9])([0-9]+)(БО|МО)$') AS m
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) parsed_name
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WHERE m IS NOT NULL
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)
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SELECT stream, degree, number, course, enrollment_year,
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count(*) AS groups,
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array_agg(name ORDER BY name) AS names
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FROM parsed
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GROUP BY stream, degree, number, course, enrollment_year
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HAVING count(*) > 1
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ORDER BY stream, degree, course, number;
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\echo '=== 3. Группы, которые не разберутся шаблоном (потребуют ручного разбора) ==='
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WITH parsed AS (
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SELECT
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g.id,
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g.name,
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m[1] AS stream,
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m[2]::int AS course,
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m[3]::int AS number,
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m[4] AS degree
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FROM identity.groups g
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CROSS JOIN LATERAL (
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SELECT regexp_match(g.name, '^(.+)-([0-9])([0-9]+)(БО|МО)$') AS m
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) parsed_name
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)
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SELECT id, name, stream, course, number, degree
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FROM parsed
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WHERE stream IS NULL
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OR course IS NULL
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OR number IS NULL
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OR degree IS NULL
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ORDER BY name;
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\echo '=== 4. Одинаковые имена групп (после снятия UNIQUE станут допустимы) ==='
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SELECT name, count(*) AS groups
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FROM identity.groups
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GROUP BY name
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HAVING count(*) > 1
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ORDER BY name;
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\echo '=== 5. Студенты без текущей группы ==='
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SELECT s.student_no, a.login, s.last_name, s.first_name
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FROM identity.students s
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JOIN identity.accounts a ON a.id = s.account_id
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LEFT JOIN identity.enrollments e ON e.student_id = s.account_id
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WHERE e.id IS NULL
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ORDER BY s.student_no;
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\echo '=== 6. Аккаунты по ролям (до появления статусов) ==='
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SELECT role, count(*) AS accounts
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FROM identity.accounts
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GROUP BY role
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ORDER BY role;
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\echo '=== 7. Дубли номеров лабораторных (все лабы переезжают в один курс C) ==='
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SELECT number,
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count(*) AS labs,
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array_agg(id ORDER BY created_at) AS ids,
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array_agg(title ORDER BY created_at) AS titles
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FROM academic.labs
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GROUP BY number
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HAVING count(*) > 1
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ORDER BY number;
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\echo '=== 8. Лабораторные по семестрам ==='
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SELECT semester_id, number, count(*) AS labs
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FROM academic.labs
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GROUP BY semester_id, number
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HAVING count(*) > 1
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ORDER BY semester_id, number;
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\echo '=== 9. Дубли slug глав (до перехода на частичные индексы) ==='
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SELECT slug, count(*) AS chapters
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FROM academic.chapters
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GROUP BY slug
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HAVING count(*) > 1
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ORDER BY slug;
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\echo '=== 10. Объём материалов ==='
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SELECT
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(SELECT count(*) FROM academic.chapters) AS chapters,
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(SELECT count(*) FROM academic.sections) AS sections,
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(SELECT count(*) FROM academic.articles) AS articles,
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(SELECT count(*) FROM academic.article_assets) AS article_assets;
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\echo '=== 11. Активы без статьи ==='
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SELECT count(*) AS assets_without_article
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FROM academic.article_assets
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WHERE article_id IS NULL;
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\echo '=== 12. Семестры ==='
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SELECT id, title, year, active
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FROM academic.semesters
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ORDER BY year, title;
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